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x=110x-3x^2
We move all terms to the left:
x-(110x-3x^2)=0
We get rid of parentheses
3x^2-110x+x=0
We add all the numbers together, and all the variables
3x^2-109x=0
a = 3; b = -109; c = 0;
Δ = b2-4ac
Δ = -1092-4·3·0
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11881}=109$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-109}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+109}{2*3}=\frac{218}{6} =36+1/3 $
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